Question 1 Report
Determine the third term of a geometrical progression whose first and second term are 2 and 14 respectively
Answer Details
1st G.P. = a =2 2nd G.P. = ar − 1 = 54 2(r) = 54 r = 54/2 = 27 r = 27 3rd term = ar2 = (2) (27)2 2 × 27 × 27 = 1458