If \(y = (x^2 + 3x - 1) \div (3x + 4)\). Find dy/dx

Assessment: JAMB UTME - Mathematics - 2015 Subject: General Mathematics

Question 1 Report

(3 x^{2} + 8 x + 7) \div (3 x + 4)^{2}

x^{2} + 2 x + (1 \div (x + 1)^{2})

2 x^{2} + 4 x + (1 \div (2 x + 4)^{2})

x^{2} + 3 x + (2 \div (x + 3)^{2})

Answer Details

dy/dx

(4 x^{3} + 3 x^{2} + 2 x + 1)

=

12 x^{2} + 6 x + 2

⇒

12 x^{2} + 6 + 2

Divide both sides by 2

\frac{12 x^{2}}{2} - \frac{6 x}{2} - \frac{2}{2}

=

6 x^{2} + 3 x + 1

dy/dx
=

6 x^{2} + 3 x + 1

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