If x+y=90
Solve for (sinx+siny)2−2sinxsiny
x+y=90
---(1)
(sinx+siny)2−2sinxsiny
----(2)
x=90−y
---(3)
Expanding eqn (2)
Therefore: sin2x+sin2y+2sinxsiny−2sinxsiny
=> sin2x+sin2y
--- (4)
Substitute the value of x
in eqn (3) into eqn (4)
=> sin2(90−y)+sin2y
---(5)
Expanding eqn (5)
=> sin2(90)−sin2y+sin2y
=> sin2(90)+0
=> sin2(90)
=> (sin(90))2
=> 12
= 1