Question 1 Report
ind then equation line through (5, 7) parallel to the line 7x + 5y = 12
Answer Details
Equation (5, 7) parallel to the line 7x + 5y = 12 5Y = -7x + 12 y = −7x5 − 7 x 5 + 125 12 5 Gradient = −75 − 7 5 ∴ Required equation = y−7x−5 y − 7 x − 5 = −75 − 7 5 i.e. 5y - 35 = -7x + 35 5y + 7x = 70