ind then equation line through (5, 7) parallel to the line 7x + 5y = 12

Assessment: JAMB UTME - Mathematics - 1992 Subject: General Mathematics

Question 1 Report

ind then equation line through (5, 7) parallel to the line 7x + 5y = 12
Answer Details
Equation (5, 7) parallel to the line 7x + 5y = 12
5Y = -7x + 12
y =  − 7 x 5  +  12 5
Gradient =  − 7 5
∴ Required equation =  y − 7 x − 5  =  − 7 5  i.e. 5y - 35 = -7x + 35
5y + 7x = 70

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