What is the value of x satisfying the equation 42x43x 4 2 x 4 3 x = 2?

Question 1 Report

What is the value of x satisfying the equation $\frac{4^{2 x}}{4^{3 x}}$ = 2?

-2

\frac{1}{2}

\frac{1}{2}

Answer Details

$\frac{4^{2 x}}{4^{3 x}}$ = 2
42x - 3x = 2
4-x = 2
(22)-x
= 21
Equating coefficients: -2x = 1
x = - $\frac{1}{2}$

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