If cos θ θ = √32 3 2 and θ θ is less than 90o. Calculate cos90−θsin2θ

Question 1 Report

If cos $θ$ = $\frac{\sqrt{3}}{2}$ and $θ$ is less than 90o. Calculate cos $\frac{90 - θ}{s i n^{2} θ}$

\frac{4}{\sqrt{3}}

\sqrt{\frac{3}{2}}

\sqrt{\frac{76}{2}}

4

\sqrt{\frac{76}{2}}

Answer Details

cos $\frac{90 - θ}{s i n^{2} θ}$
= $\frac{\tan θ}{s i n^{2} θ}$
Sin2 $θ$ = $\frac{1}{4}$
$\frac{c o s (90 - θ)}{s i n^{2} θ}$
= $\frac{1}{\sqrt{3}}$
= $\frac{4}{\sqrt{3}}$

Read lesson note on Sine, Cosine And Tangent Of An Angle (WAEC)

Read lesson note on Trigonometry (JAMB)

Sine, Cosine And Tangent Of An Angle

Trigonometry

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