If \( \cos \theta = \frac{\sqrt{3}}{2} \) and \( \theta \) is less than 90o. Calculate \( \cos \frac{90-\theta}{\sin^2\theta} \)

Assessment: JAMB UTME - Mathematics - 1985 Subject: General Mathematics

Question 1 Report

If \( \cos \theta = \frac{\sqrt{3}}{2} \) and \( \theta \) is less than 90^o. Calculate \( \cos \frac{90-\theta}{\sin^2\theta} \)

\frac{4}{\sqrt{3}}

\sqrt{\frac{3}{2}}

\sqrt{\frac{76}{2}}

4

\sqrt{\frac{76}{2}}

Answer Details

cos

\frac{90 - θ}{s i n^{2} θ}

=

\frac{\tan θ}{s i n^{2} θ}

Sin2

θ

=

\frac{1}{4}

\frac{c o s (90 - θ)}{s i n^{2} θ}

=

\frac{1}{\sqrt{3}}

=

\frac{4}{\sqrt{3}}

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