Question 1 Report
If cos θ θ = √32 3 2 and θ θ is less than 90o. Calculate cos90−θsin2θ
Answer Details
cos90−θsin2θ 90 − θ s i n 2 θ = tanθsin2θ tan θ s i n 2 θ Sin2θ θ =14 1 4 cos(90−θ)sin2θ c o s ( 90 − θ ) s i n 2 θ = 1√3 1 3 = 4√3