Question 1 Report
Find the values of p for which the equation x2 - (p - 2)x + 2p + 1 = 0
(4, 5)
Answer Details
Equal roots implies b2 - 4ac = 0 a = 1b = - (p - 2), c = 2p + 1 [-(p - 2)]2 - 4 x 1 x (2p + 1) = 0 p2 - 4p + 4 - 4(2p + 1) = 0 p2 - 4p = 4 - 8p - 4 = 0 p2 - 12p = 0 p(p - 12) = 0 p = 0 or 12
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