Find the values of p for which the equation x2 - (p - 2)x + 2p + 1 = 0

Find the values of p for which the equation x2 - (p - 2)x + 2p + 1 = 0

Answer Details

Equal roots implies b2 - 4ac = 0
a = 1b = - (p - 2), c = 2p + 1
[-(p - 2)]2 - 4 x 1 x (2p + 1) = 0
p2 - 4p + 4 - 4(2p + 1) = 0
p2 - 4p = 4 - 8p - 4 = 0
p2 - 12p = 0
p(p - 12) = 0
p = 0 or 12