In the figure, PQ is the tangent from P to the circle QRS with SR as its diameter. If QRS = θ θ ∘ ∘ and RQP = ϕ ϕ ∘ ∘ , which of the following relationships...

Question 1 Report

In the figure, PQ is the tangent from P to the circle QRS with SR as its diameter. If QRS = $θ$ $^{\circ}$ and RQP = $ϕ$ $^{\circ}$ , which of the following relationships between $θ$ $^{\circ}$ and $ϕ$ $^{\circ}$ is correct

θ

^{\circ}

+

ϕ

^{\circ}

= 902

ϕ

^{\circ}

= 902 - 2

θ

^{\circ}

θ

^{\circ}

=

ϕ

^{\circ}

ϕ

^{\circ}

= 2

θ

^{\circ}

θ

^{\circ}

+ 2

ϕ

^{\circ}

Answer Details

180 - $ϕ$ $^{\circ}$ = $θ$ $^{\circ}$ + $ϕ$ $^{\circ}$ (Sum of opposite interior angle equal to its exterior angle)

180 = 2 $ϕ$ + $θ$ $^{\circ}$

Read lesson note on Introductory Calculus (WAEC)

Read lesson note on Trigonometry (JAMB)

Read lesson note on Circles (WAEC)

Introductory Calculus

Trigonometry

Circles

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