What is the nth term of the progression 27, 9, 3,......?

Assessment: JAMB UTME - Mathematics - 1991 Subject: General Mathematics

Question 1 Report

What is the nth term of the progression 27, 9, 3,......?
Answer Details
The given progression is decreasing by a factor of 3 in each term, starting from 27. Therefore, the nth term can be calculated by multiplying 27 by 1/3 raised to the power of (n-1). This is because in the nth term, the factor of 3 has been applied (n-1) times to the first term 27. Therefore, the answer is: 27 x (1/3)^(n-1)

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