If 3 gallons of spirit containing 20% water are... | JAMB UTME - Mathematics - 1991

Question 1 Report

If 3 gallons of spirit containing 20% water are added to 5 gallons of another spirit containing 15% water, what percentage of the mixture is water?

\frac{4}{5}

\frac{7}{8}

\frac{1}{8}

\frac{7}{8}

Answer Details

% of water in the mixture
= $\frac{Total Amount of water}{Total quantity of spirit}$ x $\frac{100}{1}$
$\frac{3 (\frac{20}{100}) + 5 (\frac{15}{100})}{3 + 5}$ x $\frac{100}{1}$
= $\frac{\frac{6}{10} + \frac{75}{100}}{8}$ x $\frac{100}{1}$
= $\frac{0.6 + 0.75}{8}$ x $\frac{100}{1}$

= $\frac{1.35}{8}$ x $\frac{100}{1}$
= $\frac{33.75}{2}$
= 16.875
= 16 $\frac{7}{8}$

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If 3 gallons of spirit containing 20% water are added to 5 gallons of another spirit containing 15% water, what percentage of the mixture is water?

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