Fifty boxes each of 50 bolts were inspected for the number which were defective. The following was the result: No. defective per box456789No. of boxes271710...

Fifty boxes each of 50 bolts were inspected for the number which were defective. The following was the result:

$\begin{array}{ccccccc}\text{No. defective per box}& 4& 5& 6& 7& 8& 9\\ \text{No. of boxes}& 2& 7& 17& 10& 8& 6\end{array}$

Find the percentage of boxes containing at least 5 defective bolts each.

Answer Details

To find the percentage of boxes containing at least 5 defective bolts each, we need to first add up the number of boxes that have 5, 6, 7, 8, or 9 defective bolts. These are the boxes that contain at least 5 defective bolts. From the table, we can see that there are: - 7 boxes with 5 defective bolts - 17 boxes with 6 defective bolts - 10 boxes with 7 defective bolts - 8 boxes with 8 defective bolts - 6 boxes with 9 defective bolts Adding these up, we get a total of 7+17+10+8+6 = 48 boxes. Therefore, out of the 50 boxes that were inspected, 48 of them contain at least 5 defective bolts each. To find the percentage, we can use the formula: percentage = (part/whole) x 100 In this case, the "part" is the number of boxes containing at least 5 defective bolts (48), and the "whole" is the total number of boxes inspected (50). Substituting in the values, we get: percentage = (48/50) x 100 = 96% Therefore, the answer is 96%, option (A).