In this figure, \(PQ = PR = PS\) and \(\angle SRT = 68^\circ\). Find \(\angle QPS\).

Assessment: JAMB UTME - Mathematics - 1991 Subject: General Mathematics

Question 1 Report

In this figure, \(PQ = PR = PS\) and \(\angle SRT = 68^\circ\). Find \(\angle QPS\).

Answer Details
Since PQRS is quadrilateral 2y + 2x = QPS = 360 ∘

i.e. 2(y + x) + QPS = 360 ∘

QPS = 360 ∘  - 2(y + x)

But x + y + 68 ∘  = 180 ∘

x + y = 180 ∘  - 68 ∘  = 180 ∘

x + y = 180 ∘  - 68 ∘

= 112 ∘

QPS = 360 ∘  - 2(112 ∘ )

360 ∘  - 224 ∘  = 136

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