The equivalent capacitance of the capacitors in the circuit above

The equivalent capacitance of the capacitors in the circuit above

Answer Details

apacitance in parallel = one at the top + one under = 2C

The two in the middle are in series = C2 $\frac{C}{2}$

The equivalent capacitance of the capacitors in the circuit above = C2 $\frac{C}{2}$ + 2C = 52 $\frac{5}{2}$C