The stress experienced by a wire of diameter yπ m loaded by a weight y2 N is

Assessment: JAMB UTME - Physics - 2024 Subject: Physics

Question 1 Report

The stress experienced by a wire of diameter 

yπ
m loaded by a weight y2
N is
Answer Details

Stress is defined as the force applied per unit area. In the context of a wire being loaded by a weight, the weight acts as the force exerted, and the cross-sectional area of the wire is the area over which this force is distributed.


Force (F): This is given by the weight, which is y2 N.


Cross-sectional Area (A): For a wire with a diameter, the area can be calculated using the formula for the area of a circle: A = πr2, where r is the radius of the wire.


Given the diameter of the wire as yπ meters, the radius (r) is half of the diameter:


r = (yπ)/2


So, the area (A) is:


A = π[(yπ)/2]2


Simplifying the area:


A = π(y2π2/4)
A = y2π3/4


Stress (σ) is given by the formula:


σ = F/A


Substituting the given weight (force) and the calculated area:


σ = (y2) / (y2π3/4)


By simplifying the expression:


σ = (4y2) / (y2π3)


Cancel out y2 from numerator and denominator:


σ = 4/π2 Nm−2


Thus, the correct stress experienced by the wire is 4π Nm−2, as provided in one of the options. The explanation shows clearly how the force and area are used to derive the stress experienced by the wire.

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