(a) Given that sin y = \(\frac{8}{17}\) find the value of \(\frac{tan y}{1 + 2 tan y}\) (b) An amount of N300,000.00 was shared among Otobo, Ada and Adeola....
Question 1 Report
(a) Given that sin y = \(\frac{8}{17}\) find the value of \(\frac{tan y}{1 + 2 tan y}\)
(b) An amount of N300,000.00 was shared among Otobo, Ada and Adeola. Otobo received N60,000.00, Ada received \(\frac{5}{10}\) of the remainder, while the rest went to Adeola. In what ratio was the money shared?
Answer Details
(a) \(\sin y=\dfrac{8}{17}\). Using a \(8\)-\(15\)-\(17\) right triangle, \(\cos y=\dfrac{15}{17}\) and \(\tan y=\dfrac{8}{15}\).
\(\dfrac{\tan y}{1+2\tan y}=\dfrac{\frac{8}{15}}{1+\frac{16}{15}}=\dfrac{\frac{8}{15}}{\frac{31}{15}}=\dfrac{8}{31}\).
(b) \(\text{N}300{,}000\) shared. Otobo \(=\text{N}60{,}000\); remainder \(=\text{N}240{,}000\).
Ada \(=\dfrac{5}{10}\times 240000=\text{N}120{,}000\); Adeola \(=240000-120000=\text{N}120{,}000\).
Ratio Otobo : Ada : Adeola \(=60000:120000:120000=\mathbf{1:2:2}\).
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