The ages of a group of athletes are as follows: 18, 16. 18,20, 17, 16, 19, 17, 18, 17 and 13. (a) Find the range of the distribution. (b) Draw a frequency d...

Assessment: WAEC SSCE - General Mathematics - 2019 (Essay) Subject: General Mathematics

Question 1 Report

The ages of a group of athletes are as follows: 18, 16. 18,20, 17, 16, 19, 17, 18, 17 and 13. (a) Find the range of the distribution.

(b) Draw a frequency distribution table for the data.

(c) What is the median age?

(d) Calculate, correct to two decimal places, the;

(i) mean age:

(ii) standard deviation.

 

Answer Details

Data (11 athletes): 18, 16, 18, 20, 17, 16, 19, 17, 18, 17, 13.

(a) Range \(=\) highest \(-\) lowest \(=20-13=7\).

(b) Frequency distribution table

Age (x)131617181920
Frequency (f)123311

(c) Median. Arranged: 13, 16, 16, 17, 17, 17, 18, 18, 18, 19, 20. With \(n=11\), the median is the \(6^{th}\) value \(= \mathbf{17}\).

(d)(i) Mean. \(\sum fx = 13+32+51+54+19+20 = 189\), \(\sum f = 11\).

\(\bar{x}=\dfrac{189}{11}=17.1818\ldots \approx \mathbf{17.18}\).

(d)(ii) Standard deviation. \(\sum fx^{2}=169+512+867+972+361+400=3281\).

\(\sigma=\sqrt{\dfrac{\sum fx^{2}}{n}-\bar{x}^{2}}=\sqrt{\dfrac{3281}{11}-\left(\dfrac{189}{11}\right)^{2}}=\sqrt{298.2727-295.2149}=\sqrt{3.0579}\).

\(\sigma \approx \mathbf{1.75}\) (2 d.p.).

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