Make q the subject of the relation t = (pqr..

Question 1 Report

Make q the subject of the relation t = $\sqrt{(\frac{p q}{r} - r^{2} q)}$

q =

\frac{r t^{2}}{p - r^{3}}

q =

\frac{p - r^{3}}{r t^{2}}

q =

\frac{t^{2}}{p - r^{3}}

q =

\frac{r t}{p - r^{3}}

Answer Details

t = $\sqrt{(\frac{p q}{r} - r^{2} q)}$

Take the square of both sides

t $^{2}$ = $\frac{p q}{r}$ - r $^{2}$ q

t $^{2}$ = $\frac{p q - r^{3} q}{r}$

cross multiply

rt $^{2}$ = pq - r $^{3}$ q = q(p - r $^{3}$ )

q = $\frac{r t^{2}}{p - r^{3}}$

Make q the subject of the relation t = (pqr−r2q)−−−−−−−−√