Differentiate \( \frac{5x^3+x^2}{x} \), x ≠ 0 with respect to x.

Assessment: WAEC SSCE - Further Mathematics - 2022 (Objective) Subject: Further Mathematics

Question 1 Report

Differentiate \( \frac{5x^3+x^2}{x} \), x ≠ 0 with respect to x.

Answer Details

5x3+x2x
 → 5x3x+x2x

5x2
 + x 

Then dy/dx = 10x + 1

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