Question 1 Report
If \( \log_{10}(3x+1) + \log_{10}4 = \log_{10}(9x+2) \), find the value of x
log10(3x+1)+log104=log10(9x+2)
log104(3x+1)=log10(9x+2)
4(3x+1) = 9x + 2
12x -4 = 9x + 2
12x - 9x = 2 + 4
3x = 6
x = 2
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