The first, second and third terms of an exponential sequence (G.P) are (x - 4), (x + 2), and (3x + 1) respectively. Find the values of x.

Assessment: WAEC SSCE - Further Mathematics - 2022 Subject: Further Mathematics

Question 1 Report

\frac{- 1}{2}, 8

\frac{1}{2}, - 8

\frac{- 1}{2}, - 8

\frac{1}{2}, 8

Answer Details

U1 = x - 4
U2 = x + 2
U3 = 3x + 1

$\frac{u_{2}}{u_{1}} = \frac{u_{3}}{u_{2}}$

$\frac{x + 2}{x - 4} = \frac{3 x + 1}{x + 2}$

(x+2)(x+2) = (x-4)(3x+1)
x $^{2}$ + 4x + 4 = 3x2 - 11x - 4
collecting like terms
2x $^{2}$ - 15x - 8 =0
2x $^{2}$ + x - 16x - 8 = 0
x(2x + 1) - 8(2x + 1) = 0
(x-8)(2x+1) = 0

x = ( $\frac{- 1}{2}, 8$ )

Read lesson note on Polynomial Functions (WAEC)

Polynomial Functions

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The first, second and third terms of an exponential sequence (G.P) are (x - 4), (x + 2), and (3x + 1) respectively. Find the values of x.

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