Question 1 Report
Solve: 32x−2−28(3x−2)+3=0
Answer Details
32x−2−28(3x−2)+3=0
32x32−28.3x32+3=0
32x9−28.3x9+3=0
let p = 3x
p29−28p9+3=0
multiply through by 9p2 2 - 28p + 27 = 0p2 2 - p - 27p + 27 = 0p (p - 1) - 27(p - 1) = 0(p-1)(p-27) = 0p = 1 or 27when p = 1p = 3x 3x = 13x = 30 0 x = 0when p = 273x = 273x = 33x = 3
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