Solve: \(4\sin^2\theta + 1 = 2\), where \(0º < \theta < 180º\)

Assessment: WAEC SSCE - Further Mathematics - 2022 (Objective) Subject: Further Mathematics

Question 1 Report

Solve: \(4\sin^2\theta + 1 = 2\), where \(0º < \theta < 180º\)

Answer Details

4sin2
2
θ + 1 = 2

4sin2
θ  = 2 - 1

4sin2 2 θ = 1

s√in2θ
 = 14−−√

sinθ = 12

θ = sin−112

θ = 30º 0r 150º

Download The App On Google Playstore

Everything you need to excel in your exams

Green Bridge CBT Mobile App
Personalized AI Learning Chat Assistant
200,000+ Exam Questions Across IGCSE, JAMB, WAEC & NECO
Over 3,900 Lesson Notes
Offline Support - Learn Anytime, Anywhere
Green Bridge Timetable
Literature Summaries & Potential Questions
Track Your Performance & Progress
In-depth Explanations for Comprehensive Learning