Evaluate \( \int_{-1}^{0} (x + 1)(x - 2)\,dx \)

Assessment: WAEC SSCE - Further Mathematics - 2022 (Objective) Subject: Further Mathematics

Question 1 Report

Evaluate \( \int_{-1}^{0} (x + 1)(x - 2)\,dx \)

Answer Details

∫0−1 ∫ − 1 0  (x + 1)(x - 2) dx

= ∫0−1 ∫ − 1 0  x2−x−2
dx

Integrated x2−x−2
 = x33−x22−2

= (0 - 0 - 0) - ( -13 - 12 + 2)

 

= 0 - ( 76 ) = -76

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