If g(x) = √(1-x2 2 ), find the domain of g(x)

Question 1 Report

If g(x) = √(1-x $^{2}$ ), find the domain of g(x)

x < -1 or x > 1

x ≤ -1 or x ≥1

-1 ≤ x ≤ 1

-1 < x < 1

Answer Details

1 - x $^{2}$ ≥ 0
-x $^{2}$ ≥ -1
x $^{2}$ ≤ 1
√x $^{2}$ ≤ 1
|x| ≤ 1
-1 ≤ x ≤ 1

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