Find the tension in the two cords shown in ..

Question 1 Report

Find the tension in the two cords shown in the figure above. Neglect the mass of the cords, and assume that the angle is 38° and the mass m is 220 kg

[Take g = 9.8 ms-2]

T_{1}

= 2864 N,

T_{2}

= 3612 N

T_{1}

= 3612 N,

T_{2}

= 2864 N

T_{1}

= 3502 N,

T_{2}

= 2760 N

T_{1}

= 2760 N,

T_{2}

= 3502 N

Answer Details

W = mg = 220 x 9.8 = 2156 N

⇒Sin 38º = $\frac{2156}{T_{1}}$

⇒ $T_{1}$ = $\frac{2156}{S i n 38}$

⇒ $T_{1}$ = 3502 N

Cos 38º = $\frac{T_{2}}{T_{1}}$

⇒ $T_{2}$ = 3502 x Cos 38º

⇒ $T_{2}$ = 2760 N

; $T_{1}$ = 3502 N, $T_{2}$ = 2760 N.

Find the tension in the two cords shown in the figure above. Neglect the mass of the cords, and assume that the angle is 38° and the mass m is 220 kg [Take ...