Given that S = 3t2 + 5t - 10 is displacement of a particle in metres, calculate it initial velocity.

Given that S = 3t2 $\mathrm{<br>}{\mathrm{<br>}}^{\mathrm{<br>}}$ + 5t - 10 is displacement of a particle in metres, calculate it initial velocity.

Answer Details

To calculate the initial velocity of the particle, we need to find the first derivative of the displacement equation. The first derivative of the equation 3t^2 + 5t - 10 would give us the velocity equation.

The derivative of 3t^2 is 6t, the derivative of 5t is 5, and the derivative of a constant like -10 is 0.

So, the velocity equation would be 6t + 5. This is the initial velocity of the particle, which is 5 m/s.