Solve for k in the equation 18k+2 = 1

Question 1 Report

Solve for k in the equation ${\frac{1}{8}}^{k + 2}$ = 1

2

-4

-2

4

Answer Details

$(8^{- 1})^{k + 2}$ = $(8^{0})$

base 8 cancel out on both sides

-1(k+2) = 0

-k -2 = 0

: k = -2

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