The probability that Abiola will be late to the office on a given day is 2/5. In a given working week of six days, find, correct to four significant figures...

he will be late to office = 2/5
he will not be late to office is = 1 - 2/5 = 3/5

If he will be late for 3 days only, he will also not be late for 3 days

25 $\frac{\mathrm{<br>}}{}$ * 25 $\frac{\mathrm{<br>}}{}$ * 25 $\frac{\mathrm{<br>}}{}$ * 35 $\frac{\mathrm{<br>}}{}$ * 35 $\frac{\mathrm{<br>}}{}$ * 35 $\frac{\mathrm{<br>}}{}$ 

p = 0.0138

(b)   not be late to office is = 1 - 2/5 = 3/5

35 * 35 * 35 * 35 $\frac{\mathrm{<br>}}{}$ * 35 $\frac{\mathrm{<br>}}{}$ * 35 

p = 0.0467

(c) be late to office = 2/5

25 $\frac{\mathrm{<br>}}{}$ * 25 $\frac{\mathrm{<br>}}{}$ * 25 $\frac{\mathrm{<br>}}{}$ * 25 $\frac{\mathrm{<br>}}{}$ * 25 $\frac{\mathrm{<br>}}{}$ * 25 $\frac{\mathrm{<br>}}{}$ 

p = 0.0041