Question 1 Report
Evaluate: \( \lim_{x \to -2} \frac{x^3 + 8}{x + 2} \).
x3+8x+2
x3 + 8 = x3 + 23
recall that
x3 + y3 = (x+y)(x2 - xy + y2)
x = x, y = 2
x3 + 8 = (x+2)(x3 - 2(x) + 22)
x3+8x+2=(x+2)(x3−2(x)+22)x+2 - 2x + 4
x = -2
(-2)2 - 2(2) + 4 = 4 - 4 + 4
= 4
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