If x =3, y = 2 and z = 4 what is the value of \(3x^{2}-2y+z\)

If x =3, y = 2 and z = 4 what is the value of \(3x^{2}-2y+z\)

Answer Details

Substituting x = 3, y = 2 and z = 4 into the expression \(3x^{2}-2y+z\), we get: $$3(3)^2 - 2(2) + 4 = 27 - 4 + 4 = 27$$ Therefore, the value of \(3x^{2}-2y+z\) when x = 3, y = 2 and z = 4 is 27. The correct option is (b) 27.