Question 1 Report
Work out the equation of a straight line. The diagram shows the two points and the line through them.
The line passes through the points \((2, -1)\) and \((6, 11)\). Give your answer in the form \(y = mx + c\).
First find the gradient from the two given points:
\[m=\frac{11-(-1)}{6-2}=\frac{12}{4}=3\] [M1][A1]
Use \(y=mx+c\) and substitute \((2,-1)\):
\[-1=3(2)+c\]
\[c=-7\]
Therefore the equation is:
\[y=3x-7\] [A1]
A check using \(x=6\) gives \(3(6)-7=11\), which matches the other point.
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