The compound shown in the question is 2-butanone, also known as methyl ethyl ketone. The oxidation of 2-butanone produces 2-butanal, also known as butyraldehyde. The carbonyl group (C=O) in the 2-butanone is converted to an aldehyde group (-CHO) during the oxidation reaction. Therefore, the correct answer is 2-butanal.
