Na2CO3(g) + 2HCl(aq) → 2NaCl(aq) + H2O(l) + CO2(g) How many moles of sodium trioxocarbonate (IV) are there in a 25 cm3 solution which required 10cm3 of 0.05...

Question 1 Report

Na2CO3(g) + 2HCl(aq) → 2NaCl(aq) + H2O(l) + CO2(g)

How many moles of sodium trioxocarbonate (IV) are there in a 25 cm3 solution which required 10cm3 of 0.05 mol dm-3 hydrochloric acid solution to neutralize it?

1.000 mole

0.100 mole

0.010 mole

0.111 mole

Answer Details

$\frac{C_{A} V_{A}}{C_{B} V_{B}} = \frac{a}{b}$

$\frac{0.05 \times 10}{C_{B} \times 25} = \frac{2}{1}$

50CB = 0.5

CB = $\frac{0.5}{50} = \frac{5}{100}$

= 0.01

Read lesson note on Separation Of Mixtures And Purification Of Chemical Substances (JAMB)

Separation Of Mixtures And Purification Of Chemical Substances

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