The following table shows the distribution of test scores in a class. Scores 1 2 3 4 5 7 8 9 10 No of pupils 1 1 5 3 \(k^{2} + 1\) 6 2 3 4 (a) If the mean s...

Assessment: WAEC SSCE - General Mathematics - 2006 (Essay) Subject: General Mathematics

Question 1 Report

The following table shows the distribution of test scores in a class.

Scores 1 2 3 4 5 7 8 9 10
No of pupils 1 1 5 3 \(k^{2} + 1\) 6 2 3 4

(a) If the mean score of the class is 6, find the : (i) value of k (ii) median score.

(b) Draw a bar chart for the distribution.

(c) If a pupil is picked at random, what is the probability that he/ she will score less than 6?

Answer Details

(a)(i) Finding the value of \(k\)

Score, \(x\)1234578910Total
Frequency, \(f\)1153\(k^2+1\)6234\(k^2+26\)
\(fx\)121512\(5k^2+5\)42162740\(5k^2+160\)

Since the mean score is 6,

\[6=\frac{5k^2+160}{k^2+26}\]

\[6k^2+156=5k^2+160\]

\[k^2=4\]

\[\therefore k=2\]

Thus, the frequency for score 5 is \(k^2+1=5\), and the total number of pupils is \(4+26=30\).

(a)(ii) Median score

Score1234578910
Cumulative frequency127101521232630

There are 30 scores. The 15th score is 5 and the 16th score is 7.

\[\text{Median}=\frac{5+7}{2}=6\]

(b) Bar chart of the distribution

graph
Bar chart showing the number of pupils at each score.

(c) Probability of scoring less than 6

The scores less than 6 are 1, 2, 3, 4 and 5.

\[\text{Number of such pupils}=1+1+5+3+5=15\]

\[P(\text{score less than }6)=\frac{15}{30}=\boxed{\frac{1}{2}}\]

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