(a) A dealer sold a car to a man and made a profit of 15%. The man then sold it to a woman for N120,175.00 at a loss of 5%. How much did the dealer buy the ...
Question 1 Report
(a) A dealer sold a car to a man and made a profit of 15%. The man then sold it to a woman for N120,175.00 at a loss of 5%. How much did the dealer buy the car?
(b) The diameter of the wheel of a car is 36cm. How many revolutions, correct to three significant figures, will it make to cover a distance of 1.05 km? [Take \(\pi = \frac{22}{7}\)].
Answer Details
(a) Work backwards. The man sold to the woman at a 5% loss for \(N120{,}175\), so this is \(95\%\) of the man's cost price (which is the dealer's selling price).
Dealer's selling price \(= \dfrac{120{,}175}{0.95} = N126{,}500\).
The dealer made a 15% profit, so \(N126{,}500 = 115\%\) of the dealer's cost price.
Dealer's cost price \(= \dfrac{126{,}500}{1.15} = \mathbf{N110{,}000.00}\).
(b) Wheel diameter \(= 36\text{ cm}\), so circumference \(= \pi d = \dfrac{22}{7}\times 36 = \dfrac{792}{7} = 113.14\text{ cm}\).
Distance \(= 1.05\text{ km} = 105{,}000\text{ cm}\).
Number of revolutions \(= \dfrac{105{,}000}{113.14} = 928.03 \approx \mathbf{928}\) (3 s.f.).
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