If 1.2 x 106J of heat energy is given off in 1 sec from a vessel maintained at a temperature gradient of 30Km-1, the surface area of the vessel is
Answer Details
Generally in thermal/heat conduction, if 1.2 x 106 J is the heat flow per seconds; 30KM-1 is the temperature gradient of the materials; and 400Wm-1K-1 the thermal conductivity of the material, then we have that: heat flow per seconds per unit area = thermal conductivity x temp. gradient i.e = 1.2 x 106Area = 400 x 30 => 400 x 30 x Area = 1.2 x 106 ∴ Area = 1.2 x 106400 x 30 Area = 100m2 or 1.0 x 102m2