An electron makes a transition from a certain energy level Ek to the ground state E0. If the frequency of emission is 8.0 x 1014Hz The energy emitted is

Answer Details

When an electron transitions from a higher energy level to a lower energy level, it emits energy in the form of electromagnetic radiation, such as light. The frequency of the emitted radiation is related to the energy difference between the two energy levels by the equation: ΔE = hf where ΔE is the energy difference between the two energy levels, h is Planck's constant, and f is the frequency of the emitted radiation. In this problem, the electron is transitioning from energy level E_k to the ground state E₀. The energy difference between these two levels is given by: ΔE = E_k - E₀ We are given the frequency of the emitted radiation as 8.0 x 10¹⁴ Hz. We can use the above equation to calculate the energy difference ΔE: ΔE = hf = (6.626 x 10^-34 J s) x (8.0 x 10^14 Hz) = 5.301 x 10^-19 J The energy emitted is the same as the energy difference ΔE between the two energy levels. Therefore, the energy emitted is 5.28 x 10^-19 J, which is closest to.