Given that young's modulus for aluminium is 7.0 x 1010Nm-2 and density is 2.7 x 103kgm-3 find the speed of the sound produced if a solid bar is struck at on...

Answer Details

The speed of sound in a solid bar depends on the Young's modulus and density of the material. The formula for the speed of sound in a solid bar is: v = √(Y/ρ) where v is the speed of sound, Y is the Young's modulus, and ρ is the density. Substituting the given values for Young's modulus and density of aluminium, we get: v = √(7.0 x 10^10 Nm^-2 / 2.7 x 10^3 kgm^-3) Simplifying the expression inside the square root, we get: v = √(2.6 x 10^7 m^2s^-2) Taking the square root, we get: v = 5100 ms^-1 Therefore, the speed of sound produced if a solid bar of aluminium is struck at one end with a hammer is 5100 ms^-1. The correct option is (A) 5.1 x 10^3 ms^-1.