(a) What is a wavefront? (b) (i) State two practical uses of glass prisms. (ii) List two factors that determine the deviation of a ray of light travelling f...

Assessment: WAEC SSCE - Physics - 2017 (Essay) Subject: Physics

Question 1 Report

(a) What is a wavefront?

(b) (i) State two practical uses of glass prisms.

(ii) List two factors that determine the deviation of a ray of light travelling from air into a triangular glass prism.

(iii) Sketch a graph to illustrate the variation of the angle of deviation d, with that of incidence, i, for a ray of light travelling from air into a triangular glass prism. Indicate on the graph the point at which the angle of incidence equal to the angle of emergence e.

 

(c) (i) Draw and label a diagram of an astronomical telescope in normal adjustment.

(ii) The angular magnification of an astronomical telescope in normal adjustment is 5. If the focal length of the objective is 100cm, calculate the:

(\(\alpha\)) focal length of the eyepiece;

(\(\beta\)) length of the telescope.

Answer Details

(a) A wavefront is a surface or locus of points in a wave which are vibrating in the same phase.

(b)(i) Two practical uses of glass prisms are:

  1. to change the direction of a beam of light, for example in binoculars or periscopes;
  2. to disperse white light into its component colours, for example in a spectrometer.

(b)(ii) The deviation produced by a triangular glass prism depends on:

  1. the angle of incidence of the ray;
  2. the refractive index of the glass prism.

The refracting angle of the prism is also a factor.

(b)(iii) The graph of angle of deviation, d, against angle of incidence, i, is shown below. The minimum point is the point at which i = e.

graph
The angle of deviation decreases to a minimum value and then increases. At the minimum deviation, the path through the prism is symmetrical and i = e.

(c)(i) Astronomical telescope in normal adjustment:

figure
Astronomical telescope in normal adjustment: the objective and eyepiece have a common focal point, and the final image is at infinity.

In normal adjustment, the real intermediate image formed by the objective lies at the first focal point of the eyepiece. The emergent rays are parallel and the final image is therefore at infinity.

(c)(ii)

For an astronomical telescope in normal adjustment,

\[M=\frac{f_o}{f_e}\]

Given \(M=5\) and \(f_o=100\text{ cm}\):

(α) Focal length of eyepiece

\[5=\frac{100}{f_e}\]

\[f_e=\frac{100}{5}=20\text{ cm}\]

(β) Length of telescope

\[L=f_o+f_e=100+20=120\text{ cm}\]

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