Question 1 Report
The nth term of the progression 42 4 2 , 73 7 3 , 104 10 4 , 135 13 5 is ..
Answer Details
Using Tn = 3n+1n+1 3 n + 1 n + 1 , T1 = 3(1)+1(1)+1=42 3 ( 1 ) + 1 ( 1 ) + 1 = 4 2 T2 = 3(2)+1(2)+1=73 3 ( 2 ) + 1 ( 2 ) + 1 = 7 3 T3 = 3(3)+1(3)+1=104
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