Question 1 Report
A chord subtends an angle of 72º at the centre of a circle of radius 24.5m. Calculate the perimeter of the minor segment. [Take π = \( \frac{22}{7} \)
From ΔOKB
sin 36° = |KB|24.5 |
|KB| = 0.5878 x 24.5
=14.4011m
Or
Length of arc = 72360∗2∗227∗24.7 72 360 ∗ 2 ∗ 22 7 ∗ 24.7
=30.8m
Perimeter = 2(14.4011) + 30.8
= 59.6022
= 59.6m
Answer Details
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