A chord subtends an angle of 72º at the centre of a circle of radius 24.5m. Calculate the perimeter of the minor segment. [Take π = \( \frac{22}{7} \)

Assessment: WAEC SSCE - General Mathematics - 2022 (Essay) Subject: General Mathematics

Question 1 Report

A chord subtends an angle of 72º at the centre of a circle of radius 24.5m. Calculate the perimeter of the minor segment. [Take π = \( \frac{22}{7} \)

Answer Details

From ΔOKB

sin 36° = |KB|24.5 |

|KB| = 0.5878 x 24.5

 =14.4011m

Or

Length of arc = 72360∗2∗227∗24.7 72 360 ∗ 2 ∗ 22 7 ∗ 24.7  

=30.8m

Perimeter = 2(14.4011) + 30.8

= 59.6022

= 59.6m

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