Question 1 Report
(a) Given that (7 -2x), 9, (5x + 17) are consecutive terms of a Geometric Progression (G. P) with common ratio, r>0, find the values of x.
(b) Two positive numbers are in the ratio 3:4. The sum of thrice the first number and twice the second is 68. Find the smaller number.
(a) r =97−2x
r = 5x+17−2x
97−2x = 5x+17−2x
9x9=(7-2x) (5x +17)
81 = 35x + 119 - 10x2 - 34x
10x2 - x - 38
(x -2)(10x+19) = 0
x = 2, x = 1910
x = 2
(b) Let the integers be x and y
x:y= 3:4
xy = 34
x = 3y4
3x + 2y=68
3( 34y)+ 2y = 68
94y + 2y = 68
9y + 8y = 272
17y = 272
y= 16
x = 34 * 16 →12
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