A point X is on the bearing 342o from a point Y. What is the bearing of Y from X?

A point X is on the bearing 342^o from a point Y. What is the bearing of Y from X?

Answer Details

If point X is on a bearing of 342^o from point Y, then point Y is on a bearing of 162^o from point X. This is because the bearing from X to Y is the opposite direction from the bearing from Y to X. Therefore, we subtract the original bearing of 342^o from 180^o to get 162^o.