Solve for t in the equation \(\frac{3}{4}t+\frac{1}{3}(21-t)\) = 11,

Assessment: WAEC SSCE - General Mathematics - 2004 (Objective) Subject: General Mathematics

Question 1 Report

Solve for t in the equation \(\frac{3}{4}t+\frac{1}{3}(21-t)\) = 11,
Answer Details
First, we simplify the left-hand side of the equation: \begin{align*} \frac{3}{4}t + \frac{1}{3}(21-t) &= 11 \\ \frac{3}{4}t + 7 - \frac{1}{3}t &= 11 \\ \frac{5}{12}t &= 4 \\ t &= \frac{4 \times 12}{5} \\ t &= \frac{48}{5} \end{align*} Therefore, the value of t is \(9\frac{3}{5}\). So, the correct answer is (d).
Read lesson note on Solution Of Linear Equations (WAEC)
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