In the diagram above, EFGH is a cyclic quadrilateral in which EH//FG, EG and FH are chords. If \( \angle FHG = 42^\circ \) and \( \angle EFH = 34^\circ \), ...
In the diagram above, EFGH is a cyclic quadrilateral in which EH//FG, EG and FH are chords. If \( \angle FHG = 42^\circ \) and \( \angle EFH = 34^\circ \), calculate \( \angle HEG \)
Answer Details
∠EFH = ∠EGH(∠s in same segment) = 34∘ ∠HEG = ∠HFG(∠s in same segment) = X also ∠HFG = ∠EHF (alternate ∠s) But ∠EHG + ∠EFG =180(opp sof a cyclic quad) 42 + x + 34 + x = 180 2x + 76 = 180 2x = 180 - 76 2x = 104 x = 52∘