In the diagram above, EFGH is a cyclic quadrilateral in which EH//FG, EG and FH are chords. If ?FHG = 42? and ?EFH = 34?, calculate ?HEG
Answer Details
∠EFH = ∠EGH(∠s in same segment) = 34∘ ∠HEG = ∠HFG(∠s in same segment) = X also ∠HFG = ∠EHF (alternate ∠s) But ∠EHG + ∠EFG =180(opp sof a cyclic quad) 42 + x + 34 + x = 180 2x + 76 = 180 2x = 180 - 76 2x = 104 x = 52∘