Find the length XZ in the triangle

Assessment: JAMB UTME - Mathematics - 1999 Subject: General Mathematics

Question 1 Report

Find the length XZ in the triangle

Answer Details
xz2 = xy2 + yx2 - 2(xy) (yz) cos 120 ∘

= 22 + 12 - 2(2) (1) cos 1202

= 4 + 1 - 4x - cos 60 = 5 - 4x -  1 2

5 + 2 = 7

xz =  7 m

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