Question 1 Report
Find the length XZ in the triangle
Answer Details
xz2 = xy2 + yx2 - 2(xy) (yz) cos 120∘ ∘
= 22 + 12 - 2(2) (1) cos 1202
= 4 + 1 - 4x - cos 60 = 5 - 4x - 12 1 2
5 + 2 = 7
xz = √7 7 m
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The shaded portion in the graph is represented by
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