Question 1 Report
Find the length XY in the triangle above.
Answer Details
XY2 = XY2 + Y2 - 2XY.YZ cos 120 XZ2 = 22 + 12 - 2 x 2 1 cos 120 = 4 + 1 -2 x 2 x 1 x -cos(180 - 120) = 4 + 1 + 4 cos 60 = 5 + 4 x 1/2 = 5 + 2 = 7 XY = √7 m
