Find the length XY in the triangle above.

Assessment: JAMB UTME - Mathematics - 1999 Subject: General Mathematics

Question 1 Report

Find the length XY in the triangle above.

Answer Details
XY2 = XY2 + Y2 - 2XY.YZ cos 120
XZ2 = 22 + 12 - 2 x 2 1 cos 120
= 4 + 1 -2 x 2 x 1 x -cos(180 - 120)
= 4 + 1 + 4 cos 60
= 5 + 4 x 1/2
= 5 + 2
= 7
XY = √7 m

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