Question 1 Report
In the diagram, EFGH is a cyclic quadrilateral in which EH || FG, EG and FH are chords. If < FHG = \(424^{\circ}\) and < EFH = \(34^{\circ}\)
< GHF = < GEF = 42(angles in the same segment)
< FOG = 42 + 34 = 76(exterior angle)
< FOG = < EOH = 76(vertically opposite angle)
< EDO = 90, < DOE = = 38
< HEG = 90 - 38 = 52
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