Find the derivative of y = sin(2x3 + 3x - 4)

Find the derivative of y = sin(2x3 + 3x - 4)

Answer Details

y = sin (2x3 + 3x - 4)
let u = 2x3 + 3x - 4
∴du/dx = 6x2
y = sin U
dy/du = cos U
dy/dx = du/dx * dy/dy
∴dy/dx = (6x2 + 3) cos U
= (6x2 + 3)cos(2x3 + 3x - 4)