What is the probability that an integer x,(1 ≤ ≤ x ≤ ≤ 20) chosen at random is divisible by both 2 and 3?

What is the probability that an integer x,(1 $\le$ x $\le$ 20) chosen at random is divisible by both 2 and 3?

Answer Details

We need to find the probability that an integer between 1 and 20 chosen at random is divisible by both 2 and 3. The integers that are divisible by 2 and 3 are: 6, 12, and 18. Therefore, there are three integers that satisfy this condition. Since there are 20 integers in total, the probability of selecting one of these three integers at random is 3/20. Therefore, the answer is option (C) 3/20.